document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339625>Question 339625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the value of r so that the line (2,3) an (r,-3) has a slope perpindicular to the graph y= -1/6x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243299 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243299\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for two lines to be perpedicular the product of their slopes must equal -1<BR>\n" );
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document.write( "So the line perpedicular to y=-1/6+3 must have slope = 6<BR>\n" );
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document.write( "slope =change in y direction/change in x direction<BR>\n" );
document.write( "(-3-3)/(r-2)=6=slope<BR>\n" );
document.write( "-6/(r-2)=6<BR>\n" );
document.write( "-6/6=r-2<BR>\n" );
document.write( "-1+2=r<BR>\n" );
document.write( "r=1 </SPAN>\n" );
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