document.write( "Question 339560: The perimeter of a college athletic field is 92 meters and the length is 16 m more than the width. Find the length and width. What is the width? \n" ); document.write( "
Algebra.Com's Answer #243284 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Hint: The formula for the perimeter of a rectangle is \"P=2L%2B2W\" where 'P' is the perimeter of the rectangle, L is the length, and W is the width.\r
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\n" ); document.write( "\n" ); document.write( "Since \"The perimeter of a college athletic field is 92 meters and the length is 16 m more than the width\", we know that \"P=92\" and \"L=W%2B16\". Plug this info into the formula above to get \"92=2%28W%2B16%29%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website. \r
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