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document.write( "Kim bought a total of $2.65 worth of postage stamps in four denominations. If she bought an equal number of 5-cent and 25-cent stamps and twice as many 10-cent stamps as 5-cent stamps, what is the least number of 1-cent stamps she could have bought ?\r
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document.write( "(A) 5(B) 10(C) 15(D) 20(E) 25 \r
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document.write( "Could you explain the above problem Thanks\r
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Algebra.Com's Answer #243280 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Let x = the number of 1-cent stamps\r\n" ); document.write( "Let y = the number of 5-cent stamps and the number of 25-cent stamps\r\n" ); document.write( "\r\n" ); document.write( "Then 2y = the number of 10-cent stamps\r\n" ); document.write( "\r\n" ); document.write( "1x + 5y + 25y + 10(2y) = 265\r\n" ); document.write( " x + 30y + 20y = 265\r\n" ); document.write( " x + 50y = 265\r\n" ); document.write( " x = 265 - 50y\r\n" ); document.write( "\r\n" ); document.write( "x will be the least possible when what we must subtract from 265\r\n" ); document.write( "namely 50y is as large as possible. That will be when y is as large\r\n" ); document.write( "as possible. Since x must not be negative:\r\n" ); document.write( "\r\n" ); document.write( " x > 0 \r\n" ); document.write( " 265 - 50y > 0\r\n" ); document.write( " 265 - 50y > 0\r\n" ); document.write( " -50y > -265 \r\n" ); document.write( " y <\n" ); document.write( " |