document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38788>Question 38788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 4 cm. longer than the one leg and 18 cm. longer than the other leg. Find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24328 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the shortest leg x.<BR>\n" );
document.write( "The hypotenuse is x + 18.<BR>\n" );
document.write( "The other leg is x + 14 since it is only 4 less than the hypotenuse.<BR>\n" );
document.write( "Now apply the Pythagorean Theorem:  a^2 + b^2 = c^2 and we get<BR>\n" );
document.write( "x^2 + (x + 14)^2 = (x + 18)^2<BR>\n" );
document.write( "x^2 + x^2 + 28x + 196 = x^2 + 36x + 324<BR>\n" );
document.write( "now collecting and solving we get<BR>\n" );
document.write( "x^2 - 8x - 128 = 0<BR>\n" );
document.write( "(x - 16)(x + 8) = 0<BR>\n" );
document.write( "x = 16 or x = -8<BR>\n" );
document.write( "but distance is never negative so the short leg is 16 and the longer leg is 30.  The hypotenuse is 34. </SPAN>\n" );
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