document.write( "Question 339328: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
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document.write( "Compute the probability of each of the following events: \r
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document.write( "Event : The sum is greater than 5 .
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document.write( "Event : The sum is divisible by 6.
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document.write( "Write your answers as exact fractions. \n" );
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Algebra.Com's Answer #243246 by edjones(8007) You can put this solution on YOUR website! sum>5 \n" ); document.write( "2:1/36 \n" ); document.write( "3:2/36 \n" ); document.write( "4:3/36 \n" ); document.write( "5:4/36 \n" ); document.write( "--------add \n" ); document.write( "==10/36 \n" ); document.write( "1 - 10/36 = 26/36 = 13/18 \n" ); document.write( ". \n" ); document.write( "sum divisible by 6 \n" ); document.write( "6:5/36 \n" ); document.write( "12:1/36 \n" ); document.write( "--------add \n" ); document.write( "==6/36=1/6 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |