document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339409>Question 339409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find (f of g) (3) when f(x)= 3x^2-2x+1 and g(x)=sqrt(5x-6) \r<BR>\n" );
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document.write( "sqrt: means square root  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243228 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find (f of g) (3) when f(x)= 3x^2-2x+1 and g(x)=sqrt(5x-6) <BR>\n" );
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document.write( "fog(3) = f[g(3)]<BR>\n" );
document.write( "= f[sqrt(15-6)]<BR>\n" );
document.write( "= f[sqrt(9)]<BR>\n" );
document.write( "= f[3]<BR>\n" );
document.write( "= 3(3^2)-2(3)+1<BR>\n" );
document.write( "= 27-6+1<BR>\n" );
document.write( "= 22<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============== </SPAN>\n" );
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