document.write( "Question 339383: At 6:00 a.m. a man left a town A and travelled toward a town B 19 miles away. At 6:30 another man started from B and travelled toward A. The two men met on the road at 8:30 a.m. If the rate of the first traveller is 1/2 mile per hour less than that of the second,find the rate of each.\r
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document.write( "Pls. answer.Thank you. \n" );
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Algebra.Com's Answer #243215 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Write an equation for both men: \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------- \n" ); document.write( "I can rewrite the equations of motion \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, since both are equal to \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The 1st man's rate is 4 mi/hr \n" ); document.write( "The 2nd man's rate is 4.5 mi/hr \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |