document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339383>Question 339383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 6:00 a.m. a man left a town A and travelled toward a town B 19 miles away. At 6:30 another man started from B and travelled toward A. The two men met on the road at 8:30 a.m. If the rate of the first traveller is 1/2 mile per hour less than that of the second,find the rate of each.\r<BR>\n" );
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document.write( "Pls. answer.Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243211 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 6:00 a.m. a man left a town A and traveled toward a town B 19 miles away. At 6:30 another man started from B and traveled toward A. The two men met on the road at 8:30 a.m. If the rate of the first traveler is 1/2 mile per hour less than that of the second, find the rate of each. <BR>\n" );
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document.write( "6:00 man DATA:<BR>\n" );
document.write( "time = 2.5 hrs ; rate = x mph ; distance = 2.5x miles<BR>\n" );
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document.write( "6:30 man DATA:<BR>\n" );
document.write( "time = 2 hrs ; rate = x+1/2 mph ; distance = 2(x+(1/2)) = 2x+1 miles<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "distance + distance = 19 miles<BR>\n" );
document.write( "2.5x + 2x+1 = 19 miles<BR>\n" );
document.write( "4.5x = 18<BR>\n" );
document.write( "x = 4 mph (rate of the 6:00 man)<BR>\n" );
document.write( "x+(1/2) = 4.5 mph (rate of the 6:30 man)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
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