document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339363>Question 339363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A gardener marks out a new section of lawn that is supposed to be a rectangle with sides of length 15m and 10m. To check he has marked out a rectangle he measures the length of the diagonal. How long should this be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243206 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Apply the Pythagorean theorem:<BR>\n" );
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document.write( "Let d = length of diagonal<BR>\n" );
document.write( "then<BR>\n" );
document.write( "d^2 = 15^2 + 10^2<BR>\n" );
document.write( "d^2 = 225 + 100<BR>\n" );
document.write( "d^2 = 325<BR>\n" );
document.write( "d = 18.028 m </SPAN>\n" );
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