document.write( "Question 338998: A discount store sold plastic cups for $3.25 each and ceramic cups for $4.50 each.?
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document.write( "if 500 cups were sold for a total of 2,090,how many cups of each type were sold?\r
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document.write( "What was the dollar value of each type of cup sold? \n" );
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Algebra.Com's Answer #243182 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Call the number of plastic cups p.\r \n" ); document.write( "\n" ); document.write( "500 cups were sold in total, so that means that 500-p ceramic cups were sold.\r \n" ); document.write( "\n" ); document.write( "A discount store sold plastic cups for $3.25 each -at a cost of 3.25p-and ceramic cups for $4.50 each -at a cost of 4.5*(500-p)....for a total of 2,090\r \n" ); document.write( "\n" ); document.write( "So\r \n" ); document.write( "\n" ); document.write( "3.25p + 4.5(500-p) = 2090\r \n" ); document.write( "\n" ); document.write( "Now we can just solve for p....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3.25p + 2250 -4.5p = 2090 \n" ); document.write( "2250-2090 = 4.5p-3.25p \n" ); document.write( "160 = 1.25p \n" ); document.write( "p = 160/1.25 = 128\r \n" ); document.write( "\n" ); document.write( "128 plastic cups were sold for 128*3.25 = $416\r \n" ); document.write( "\n" ); document.write( "500-128 = 372 ceramic cups were sold for 372 *4.5= $1674\r \n" ); document.write( "\n" ); document.write( "Check: 416+1674 = 2090 \n" ); document.write( " \n" ); document.write( " |