document.write( "Question 339277: Solve and check.
\n" ); document.write( "√(27-3x)=x-3
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Algebra.Com's Answer #243167 by stanbon(75887) $\"\"$ $\"About$

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Solve and check.
\n" ); document.write( "√(27-3x)=x-3
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\n" ); document.write( "Square both sides to get:
\n" ); document.write( "27-3x = x^2-6x+9
\n" ); document.write( "x^2 -3x - 18 = 0
\n" ); document.write( "(x-6)(x+3) = 0
\n" ); document.write( "x = 6 or x = -3
\n" ); document.write( "----
\n" ); document.write( "Checking in sqrt(27-3x) = x-3
\n" ); document.write( "Check x = 6 ?
\n" ); document.write( "sqrt(27-18) = 6-3
\n" ); document.write( "sqrt(9) = 3
\n" ); document.write( "3 = 3
\n" ); document.write( "True
\n" ); document.write( "----------------
\n" ); document.write( "Check x = -3
\n" ); document.write( "sqrt((27+9) = -3-3
\n" ); document.write( "sqrt(36) = -6
\n" ); document.write( "6 = -6
\n" ); document.write( "False
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\n" ); document.write( "Final solution: x = 6
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\n" ); document.write( "Cheers,
\n" ); document.write( "stan H. \n" ); document.write( "

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