document.write( "Question 339116: (1) sqrt of the fraction 27/16\r
\n" ); document.write( "\n" ); document.write( "(2) 3 plus the sqrt of x^2-8x=0\r
\n" ); document.write( "\n" ); document.write( "(3) (1 minus the sqrt of x)^2\r
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\n" ); document.write( "\n" ); document.write( "How do I solve these?
\n" ); document.write( "I tried the first one and got sqrt of the fraction 3/4. Is that right? If not, show me the right steps to get the correct result. \n" ); document.write( "

Algebra.Com's Answer #243064 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
1) Find:
\n" ); document.write( " $\"sqrt%2827%2F16%29\"$
\n" ); document.write( " $\"sqrt%2827%29+=+3sqrt%283%29\"$
\n" ); document.write( " $\"sqrt%2816%29+=+4\"$ so...
\n" ); document.write( " $\"highlight%28sqrt%2827%2F16%29+=+3%2Asqrt%283%29%2F4%29%29\"$
\n" ); document.write( "2) Solve:
\n" ); document.write( " $\"3%2Bsqrt%28x%5E2-8x%29+=+0\"$ First, subtract 3 from both sides.
\n" ); document.write( " $\"sqrt%28x%5E2-8x%29+=+-3\"$ Now square both sides.
\n" ); document.write( " $\"x%5E2-8x+=+9\"$ Next, subtract 9 from both sides.
\n" ); document.write( " $\"x%5E2-8x-9+=+0\"$ Factor this trinomial.
\n" ); document.write( " $\"%28x%2B1%29%28x-9%29+=+0\"$ Now apply the zero product rule.
\n" ); document.write( " $\"x%2B1+=+0\"$ or $\"x-9+=+0\"$ so...
\n" ); document.write( " $\"highlight%28x+=+-1%29\"$ or $\"highlight%28x+=+9%29\"$
\n" ); document.write( "3) Simplify:
\n" ); document.write( " $\"%281-sqrt%28x%29%29%5E2\"$
\n" ); document.write( " $\"%281-sqrt%28x%29%29%2A%281-sqrt%28x%29%29+=+highlight%281-2%2Asqrt%28x%29%2Bx%29\"$ \n" ); document.write( "

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