document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339098>Question 339098</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has hypotenuse of length 10 feet and one<BR>\n" );
document.write( "leg in known to be 6 feet. What is the length of the other leg? What<BR>\n" );
document.write( "is the triangle's area?<BR>\n" );
document.write( "CAN YOU EXPLAIN IT TO ME STEP BY STEP </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243057 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243057\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In any right triangle, the square of the hypotenuse is equal to the sum of the squares of the two legs. This is known as the Pythagorean theorem and can be expressed in algebraic terms as:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > where c is the length of the hypotenuse and a and b are the lengths of the two legs, so, you are given the length of c (c = 10ft) and one of the legs (a = 6ft), so you can substitute the values for c and a into the formula:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c%5E2+=+a%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"c%5E2+=+a%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute c = 10 and a = 6.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E2+=+6%5E2%2Bb%5E2 ALIGN=MIDDLE  ALT=\"10%5E2+=+6%5E2%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Evaluate.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100+=+36%2Bb%5E2 ALIGN=MIDDLE  ALT=\"100+=+36%2Bb%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 36 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=64+=+b%5E2 ALIGN=MIDDLE  ALT=\"64+=+b%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now take the square root of both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2864%29+=+sqrt%28b%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2864%29+=+sqrt%28b%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > so that...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8+=+b ALIGN=MIDDLE  ALT=\"8+=+b\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+8 ALIGN=MIDDLE  ALT=\"b+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The length of the other leg is 8 feet.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );