document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339058>Question 339058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one of two complementary angles is three more than twice the other. The smaller equals _ ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243047 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two angles be A and B.<BR>\n" );
document.write( "A+B = 90 \"...two complementary angles...\" <BR>\n" );
document.write( "A = 2B+3 \"The measure of one of two complementary angles is three more than twice the other.\" Substitute this for A in the first equation and solve for angle B.<BR>\n" );
document.write( "(2B+3)+B = 90 Simplify.<BR>\n" );
document.write( "3B+3 = 90 Subtract 3 from both sides.<BR>\n" );
document.write( "3B = 87 Divide both sides by 3.<BR>\n" );
document.write( "B = 29 degrees.<BR>\n" );
document.write( "A = 2(29)+3<BR>\n" );
document.write( "A = 61 degrees.<BR>\n" );
document.write( "The smaller angle equals 29 degress. </SPAN>\n" );
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