document.write( "Question 339034: If 713^10 is multiplied out completely, what is the units digit of the resulting number?\r
\n" ); document.write( "\n" ); document.write( "(a) 0 (b) 1 (c) 3 (d) 7 (e) 9
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Algebra.Com's Answer #243027 by galactus(183)\"\" \"About 
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When looking for a units digit of a large number, use mod 10\r
\n" ); document.write( "\n" ); document.write( "Since a number divisible by 10 ends in 0, the units digit will be the remainder when divided by 10.\r
\n" ); document.write( "\n" ); document.write( "Note that 713=23*31\r
\n" ); document.write( "\n" ); document.write( "So, we have \"%2823%5E2%29%5E5%2A%2831%5E2%29%5E5=713%5E10\"\r
\n" ); document.write( "\n" ); document.write( "Powers of 31 always end in 1 and 23^2 ends in 9\r
\n" ); document.write( "\n" ); document.write( "23^2==9(mod 10) and 31==1(mod 10)\r
\n" ); document.write( "\n" ); document.write( "9*1=9\r
\n" ); document.write( "\n" ); document.write( "The last digit is 9.\r
\n" ); document.write( "\n" ); document.write( "The idea with mod arithmetic like this is to break it up into smaller powers to work with.\r
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