document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339037>Question 339037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a right triangle is 60 and the sides are x, 2x + 4, and 3x – 4, what is the area of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243025 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x +2x + 4+ 3x – 4 =60<BR>\n" );
document.write( "6x=60<BR>\n" );
document.write( "x=10<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2x+4 = 2*10+4 =24<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x-4 = 3*10-4=26\r<BR>\n" );
document.write( "\n" );
document.write( "the right triangle<BR>\n" );
document.write( "10,24,26<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area = 1/2 * 10*24<BR>\n" );
document.write( "=120 sq.units </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );