document.write( "Question 339026: a 140-second song is divided into three parts, the begining, the middle, and the end. the beginning is one-sixth as long as the end. the middle is one half as long as the end. find the length of each part \n" ); document.write( "
Algebra.Com's Answer #243020 by josmiceli(19441)\"\" \"About 
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Let beginning = \"b\"
\n" ); document.write( "Let middle = \"m\"
\n" ); document.write( "Let end = \"e\"
\n" ); document.write( "given:
\n" ); document.write( "(1) \"b+%2B+m+%2B+e+=+140\"
\n" ); document.write( "(2) \"b+=+%281%2F6%29%2Ae\"
\n" ); document.write( "(3) \"m+=+%281%2F2%29%2Ae\"
\n" ); document.write( "-----------------
\n" ); document.write( "There are 3 unknowns and 3 equations, so
\n" ); document.write( "it should be solvable
\n" ); document.write( "Substitutute (2) in (1)
\n" ); document.write( "(1) \"%281%2F6%29%2Ae+%2B+m+%2B+e+=+140\"
\n" ); document.write( "Substitute (3) in (1)
\n" ); document.write( "(1) \"%281%2F6%29%2Ae+%2B+%281%2F2%29%2Ae+%2B+e+=+140\"
\n" ); document.write( "Multiply both sides by \"6\"
\n" ); document.write( "(1) \"e+%2B+3e+%2B+6e+=+840\"
\n" ); document.write( "\"10e+=+840\"
\n" ); document.write( "\"e+=+84\"
\n" ); document.write( "And, from (2)
\n" ); document.write( "\"b+=+%281%2F6%29%2A84\"
\n" ); document.write( "\"b+=+14\"
\n" ); document.write( "From (3)
\n" ); document.write( "\"m+=+%281%2F2%29%2A84\"
\n" ); document.write( "\"m+=+42\"
\n" ); document.write( "The beginning is 14 min
\n" ); document.write( "The middle is 42 min
\n" ); document.write( "The end is 84 min
\n" ); document.write( "check:
\n" ); document.write( "(1) \"b+%2B+m+%2B+e+=+140\"
\n" ); document.write( "\"14+%2B+42+%2B+84+=+140\"
\n" ); document.write( "\"140+=+140\"
\n" ); document.write( "(2) \"b+=+%281%2F6%29%2Ae\"
\n" ); document.write( "(2) \"b+=+%281%2F6%29%2A84\"
\n" ); document.write( "\"14+=+84%2F6\"
\n" ); document.write( "\"14+=+14\"
\n" ); document.write( "(3) \"m+=+%281%2F2%29%2Ae\"
\n" ); document.write( "(3) \"42+=+%281%2F2%29%2A84\"
\n" ); document.write( "\"42+=+42\"
\n" ); document.write( "OK\r
\n" ); document.write( "\n" ); document.write( "
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