document.write( "Question 338996: Find three consecutive integers such that the sum of the squares of the second and third exceeds twice the square of the first by 41. \n" ); document.write( "
Algebra.Com's Answer #243015 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let the numbers be x, x+1 and x+2 \n" ); document.write( "(x+1)^2 + (x+2)^2 = 2x^2+41 \n" ); document.write( "x^2+2x+1+x^2+4x+4=2x^2+41 \n" ); document.write( "6x=36 \n" ); document.write( "x=6 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |