document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=339011>Question 339011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when the sum of 16 and 10 times a positive number is subtracted from the sqaure of the number,o results </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #243010 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=243010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when the sum of 16 and 10 times a positive number is subtracted from the sqaure of the number,o results\r<BR>\n" );
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document.write( "let the number be x<BR>\n" );
document.write( "x^2-(10x+16)=0<BR>\n" );
document.write( "x^2-10x-16=0<BR>\n" );
document.write( "find the roots of the equation<BR>\n" );
document.write( "x1= (10+sqrt(100+64))/2<BR>\n" );
document.write( "x1= 11.403<BR>\n" );
document.write( "x2=(10-sqrt(100+64))/2<BR>\n" );
document.write( "x2=-1.403\r<BR>\n" );
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document.write( "Check <BR>\n" );
document.write( "plug the value of 11.403 in the equation<BR>\n" );
document.write( "11.403^2-((10*11.403)+16)=.001<BR>\n" );
document.write( "The number is 11.403<BR>\n" );
document.write( "-1.403 does not satisfy . so ignore </SPAN>\n" );
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