document.write( "Question 4849: Safety Rent-A-truck rents a truck at a daily rate of $41.95 plus $.29 per mile. City Rentals rents the same size truck for $38.95 plus $.31 per mile. For what mileage is the cost the same? \n" ); document.write( "
Algebra.Com's Answer #2430 by Abbey(339)\"\" \"About 
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let x = the number of miles driven\r
\n" ); document.write( "\n" ); document.write( "safety rent-a-truck charges 41.95+.29x
\n" ); document.write( "City rental charges 38.95+.31x\r
\n" ); document.write( "\n" ); document.write( "we can set them equal to one another to determine the mileage that would make them cost the same price:
\n" ); document.write( "41.95+.29x=38.95+.31x
\n" ); document.write( "subtract.29x-38.95 from each side to get:
\n" ); document.write( "41.95-38.95=.02x
\n" ); document.write( "3=.02x\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by .02
\n" ); document.write( "150=x\r
\n" ); document.write( "\n" ); document.write( "Check this by plugging it back into both equations:
\n" ); document.write( "41.95 + .29(150) = 85.45
\n" ); document.write( "38.95+.31(150)= 85.45\r
\n" ); document.write( "\n" ); document.write( "they equal one another, so the answer is 150 miles.
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