document.write( "Question 4849: Safety Rent-A-truck rents a truck at a daily rate of $41.95 plus $.29 per mile. City Rentals rents the same size truck for $38.95 plus $.31 per mile. For what mileage is the cost the same? \n" ); document.write( "
Algebra.Com's Answer #2430 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! let x = the number of miles driven\r \n" ); document.write( "\n" ); document.write( "safety rent-a-truck charges 41.95+.29x \n" ); document.write( "City rental charges 38.95+.31x\r \n" ); document.write( "\n" ); document.write( "we can set them equal to one another to determine the mileage that would make them cost the same price: \n" ); document.write( "41.95+.29x=38.95+.31x \n" ); document.write( "subtract.29x-38.95 from each side to get: \n" ); document.write( "41.95-38.95=.02x \n" ); document.write( "3=.02x\r \n" ); document.write( "\n" ); document.write( "Divide both sides by .02 \n" ); document.write( "150=x\r \n" ); document.write( "\n" ); document.write( "Check this by plugging it back into both equations: \n" ); document.write( "41.95 + .29(150) = 85.45 \n" ); document.write( "38.95+.31(150)= 85.45\r \n" ); document.write( "\n" ); document.write( "they equal one another, so the answer is 150 miles. \n" ); document.write( " |