document.write( "Question 338993: Hello, I have a question for you.\r
\n" ); document.write( "\n" ); document.write( "A rectangular garden is 10ft longer than it is wide. Its area is 6375 ft^2. What are its dimensions?\r
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\n" ); document.write( "\n" ); document.write( "Its width equals _____________ feet and its length equals___________ feet.
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Algebra.Com's Answer #242995 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A rectangular garden is 10ft longer than it is wide. Its area is 6375 ft^2\" means that \"x%28x%2B10%29=6375\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B10%29=6375\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B10x=6375\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B10x-6375=0\" Subtract 6375 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2%2B10x-6375\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=10\", and \"C=-6375\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2810%29+%2B-+sqrt%28+%2810%29%5E2-4%281%29%28-6375%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=10\", and \"C=-6375\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100-4%281%29%28-6375%29+%29%29%2F%282%281%29%29\" Square \"10\" to get \"100\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100--25500+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-6375%29\" to get \"-25500\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100%2B25500+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%28100--25500%29\" as \"sqrt%28100%2B25500%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+25600+%29%29%2F%282%281%29%29\" Add \"100\" to \"25500\" to get \"25600\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+25600+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+160%29%2F%282%29\" Take the square root of \"25600\" to get \"160\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B+160%29%2F%282%29\" or \"x+=+%28-10+-+160%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28150%29%2F%282%29\" or \"x+=++%28-170%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+75\" or \"x+=+-85\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible solutions are \"x+=+75\" or \"x+=+-85\" \r
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\n" ); document.write( "\n" ); document.write( "However, a negative length doesn't make sense. So ignore \"x+=+-85\"\r
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\n" ); document.write( "\n" ); document.write( "So the only solution is \"x+=+75\" which means that the width is 75 ft and the length is 85 ft.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website. \r
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\n" ); document.write( "\n" ); document.write( "Jim
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