document.write( "Question 338967: Two cars enter the Florida Turnpike at Commercial Boulevard at 8AM, each heading for Wildwood. One car's average speed is 10 miles per hour more than the other's. THe faster car arrives at Wildwood at 11AM, 1/2 hour before the other car. What is the average speed of each car? How far did each car travel? \n" ); document.write( "
Algebra.Com's Answer #242980 by mananth(16946)\"\" \"About 
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let one car's speed be x
\n" ); document.write( "the other car's speed = x+10
\n" ); document.write( "..
\n" ); document.write( "time taken by faster car = 3 hours
\n" ); document.write( "time taken by slower car = 3.5 hours
\n" ); document.write( "..
\n" ); document.write( "distance = speed * time
\n" ); document.write( "the distance they travel is the same
\n" ); document.write( "3(x+10)=3.5x
\n" ); document.write( "3x+30=3.5x
\n" ); document.write( "3.5x-3x=30
\n" ); document.write( "0.5x=30
\n" ); document.write( "x=30/0.5
\n" ); document.write( "x=60 mph. speed of one car.
\n" ); document.write( "the other car's speed = x+10 = 70 mph
\n" ); document.write( "distance traveled = speed * time
\n" ); document.write( "= 70*3=210 miles
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