document.write( "Question 338323: Find square root of
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Algebra.Com's Answer #242969 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"sqrt%2864%2Ad%5E6%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2864%2Ad%5E2%2Ad%5E2%2Ad%5E2%29\" Factor \"d%5E6\" into \"d%5E2%2Ad%5E2%2Ad%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2864%29%2Asqrt%28d%5E2%29%2Asqrt%28d%5E2%29%2Asqrt%28d%5E2%29\" Break up the square root using the identity \"sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"8%2Asqrt%28d%5E2%29%2Asqrt%28d%5E2%29%2Asqrt%28d%5E2%29\" Take the square root of \"64\" to get \"8\".\r
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\n" ); document.write( "\n" ); document.write( "\"8%2Ad%2Ad%2Ad\" Take the square root of \"d%5E2\" to get \"d\".\r
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\n" ); document.write( "\n" ); document.write( "\"8d%5E3\" Rearrange and multiply the terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"sqrt%2864%2Ad%5E6%29\" simplifies to \"8d%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%2864%2Ad%5E6%29=8d%5E3\" where \"d%3E=0\".\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website. \r
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\n" ); document.write( "\n" ); document.write( "Jim
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