document.write( "Question 338915: Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8. I know the answer is 3, 5, 7, but I need the work. Thanks! \n" ); document.write( "
Algebra.Com's Answer #242910 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8\" means that \"x%28x%2B2%29=x%2B4%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29=x%2B4%2B8\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B2%29=x%2B12\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x=x%2B12\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x-x-12=0\" Get every term to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-12=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"x%5E2%2Bx-12\" is in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=1\", and \"C=-12\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%281%29%28-12%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=1\", and \"C=-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1-4%281%29%28-12%29+%29%29%2F%282%281%29%29\" Square \"1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1--48+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%28-12%29\" to get \"-48\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%2B48+%29%29%2F%282%281%29%29\" Rewrite \"sqrt%281--48%29\" as \"sqrt%281%2B48%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+49+%29%29%2F%282%281%29%29\" Add \"1\" to \"48\" to get \"49\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+49+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+7%29%2F%282%29\" Take the square root of \"49\" to get \"7\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B+7%29%2F%282%29\" or \"x+=+%28-1+-+7%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%286%29%2F%282%29\" or \"x+=++%28-8%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+3\" or \"x+=+-4\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+3\" or \"x+=+-4\" \r
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\n" ); document.write( "\n" ); document.write( "So the three consecutive odd integers are 3, 5, and 7\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website. \r
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\n" ); document.write( "\n" ); document.write( "Jim
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