document.write( "Question 338833: The first side of a triangle is 7 cm shorter than twice the second side. The third side is 4 cm longer than the first side. The perimeter is 80 cm. Find the length of each side. \n" ); document.write( "
Algebra.Com's Answer #242899 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let a, b, c = lengths of the 1st, 2nd and 3rd sides respectively \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, put in terms of a: \n" ); document.write( ": \n" ); document.write( "\"The first side of a triangle is 7 cm shorter than twice the second side.\" \n" ); document.write( "a = 2b - 7 \n" ); document.write( "2b = a + 7 \n" ); document.write( "b = \n" ); document.write( ": \n" ); document.write( "\"The third side is 4 cm longer than the first side.\" \n" ); document.write( "c = a + 4 \n" ); document.write( ": \n" ); document.write( "The perimeter is 80 cm. \n" ); document.write( "a + b + c = 80 \n" ); document.write( "Replace b & c using the above equations \n" ); document.write( "a + \n" ); document.write( "get rid of that annoying fraction, multiply by 2, results \n" ); document.write( "2a + (a+7) + 2(a+4) = 2(80) \n" ); document.write( "2a + a + 7 + 2a + 8 = 160 \n" ); document.write( "5a + 15 = 160 \n" ); document.write( "5a = 160 - 15 \n" ); document.write( "5a = 145 \n" ); document.write( "a = \n" ); document.write( "a = 29 is side a \n" ); document.write( "then \n" ); document.write( "b = \n" ); document.write( "b = \n" ); document.write( "b = 18 is side b \n" ); document.write( "and \n" ); document.write( "c = 29 + 4 \n" ); document.write( "c = 33 is side c \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if those add up to 80 \n" ); document.write( "29 + 18 + 33 = 80\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |