document.write( "Question 338835: If an integer n is divisible by both 6 and 8, then it must also be divisible by which of the following?\r
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Algebra.Com's Answer #242877 by Edwin McCravy(20055) $\"\"$ $\"About$

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If an integer n is divisible by both 6 and 8, then it must also be divisible by which of the following?\r
\n" ); document.write( "\n" ); document.write( "(A)10
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document.write( "If the positive integer is divisible by 6 and 8, then since 6 = 2×3 and\r\n" );
document.write( "8 = 2×2×2 then it has 2 as a factor at least 3 times and 3 as a factor at least\r\n" );
document.write( "one time, so the factors of any positive integer which we can be certain it is\r\n" );
document.write( "divisible by must necessarily contain 2 as a factor three or fewer times and 3\r\n" );
document.write( "no more than once.\r\n" );
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document.write( "(A) is not the correct answer.  It is not necessarily divisible by 10, since\r\n" );
document.write( "10 = 2×5 and it does not necessarily have a factor of 5.\r\n" );
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document.write( "(C) is not the correct answer.  It is not necessarily divisible by 14, since\r\n" );
document.write( "14 = 2×7 and it does not necessarily have a factor of 7.\r\n" );
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document.write( "(D) is not the correct answer.  It is not necessarily divisible by 16, since\r\n" );
document.write( "16 = 2×2×2×2 and it does not necessarily have 2 as a factor 4 times.\r\n" );
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document.write( "(E) is not the correct answer.  It is not necessarily divisible by 18, since\r\n" );
document.write( "18 = 2×3×3 and it does not necessarily have 3 as a factor 2 times.\r\n" );
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document.write( "That leaves (B) as the correct answer. It is necessarily divisible by 12, since\r\n" );
document.write( "12 = 2×2×3 and therefore doesn't have 2 as a factor more than 3 times, and it\r\n" );
document.write( "has 3 as a factor only once.\r\n" );
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document.write( "Edwin

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