document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338786>Question 338786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 times the width. If the length is decreased by 4 and width is increased by 1m, perimeter will be 66 m. Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242856 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width be x<BR>\n" );
document.write( "length is 3x<BR>\n" );
document.write( "new dimensions<BR>\n" );
document.write( "width x+1<BR>\n" );
document.write( "length 3x-4<BR>\n" );
document.write( "Perimeter = 2*(L+W)<BR>\n" );
document.write( "2*(x+1+3x-4)=66<BR>\n" );
document.write( "2*(4x-3)=66<BR>\n" );
document.write( "8x-6 = 66<BR>\n" );
document.write( "add 6 to both sides<BR>\n" );
document.write( "8x-6+6= 66+6<BR>\n" );
document.write( "8x=72<BR>\n" );
document.write( "divide by 8<BR>\n" );
document.write( "x= 9 the width<BR>\n" );
document.write( "length = 3x = 27 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );