document.write( "Question 338756: gary is 5 years older than henry.21 years ago, gary was twice as old as henry.what is the age of gary and henry.
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Algebra.Com's Answer #242846 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let Henry be x \n" ); document.write( "Gary = x+5 \n" ); document.write( ".. \n" ); document.write( "21 years ago their ages were \n" ); document.write( "Henry x-21 \n" ); document.write( "Gary (x+5-21) \n" ); document.write( ".. \n" ); document.write( "(x+5-21)= 2(x-21) \n" ); document.write( "x-16 = 2x-42 \n" ); document.write( "add +16 to both sides \n" ); document.write( "x-16+16=2x-42+16 \n" ); document.write( "x=2x-26 \n" ); document.write( "add -x to both sides \n" ); document.write( "x-x=2x-x-26 \n" ); document.write( "0=x-26 \n" ); document.write( "add 26 to both sides \n" ); document.write( "26=x-26+26 \n" ); document.write( "x= 26 Henry,s age \n" ); document.write( "Gary = 26+5 = 31 years \n" ); document.write( " |