document.write( "Question 338756: gary is 5 years older than henry.21 years ago, gary was twice as old as henry.what is the age of gary and henry.
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Algebra.Com's Answer #242846 by mananth(16946)\"\" \"About 
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Let Henry be x
\n" ); document.write( "Gary = x+5
\n" ); document.write( "..
\n" ); document.write( "21 years ago their ages were
\n" ); document.write( "Henry x-21
\n" ); document.write( "Gary (x+5-21)
\n" ); document.write( "..
\n" ); document.write( "(x+5-21)= 2(x-21)
\n" ); document.write( "x-16 = 2x-42
\n" ); document.write( "add +16 to both sides
\n" ); document.write( "x-16+16=2x-42+16
\n" ); document.write( "x=2x-26
\n" ); document.write( "add -x to both sides
\n" ); document.write( "x-x=2x-x-26
\n" ); document.write( "0=x-26
\n" ); document.write( "add 26 to both sides
\n" ); document.write( "26=x-26+26
\n" ); document.write( "x= 26 Henry,s age
\n" ); document.write( "Gary = 26+5 = 31 years
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