document.write( "Question 338750: Solve the problem
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document.write( "Given log[10]^2 = 0.3010 and log[10]^3 = 0.4771.
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document.write( "Find log[10] ^24
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document.write( "I am so confused, can someone please help me? \n" );
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Algebra.Com's Answer #242824 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve the problem \n" ); document.write( "Given log[10]^2 = 0.3010 and log[10]^3 = 0.4771. \n" ); document.write( "Find log[10] ^24 \n" ); document.write( "------------------- \n" ); document.write( "I think you mean: \n" ); document.write( "Solve the problem \n" ); document.write( "Given \n" ); document.write( "Find log(24) \n" ); document.write( "------------- \n" ); document.write( "1st, base 10 is the default base, called \"common log\", so it's not necessary to specify it. \n" ); document.write( "------------------ \n" ); document.write( "log(2) = 0.3010 and log(3) = 0.4771 is sufficient \n" ); document.write( "24 = 2*2*2*3 \n" ); document.write( "log(24) = 3*log(2) + log(3) \n" ); document.write( "log(24) =~ 1.3801 \n" ); document.write( " \n" ); document.write( " |