document.write( "Question 338750: Solve the problem
\n" ); document.write( "Given log[10]^2 = 0.3010 and log[10]^3 = 0.4771.
\n" ); document.write( "Find log[10] ^24
\n" ); document.write( "I am so confused, can someone please help me?
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Algebra.Com's Answer #242824 by Alan3354(69443)\"\" \"About 
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Solve the problem
\n" ); document.write( "Given log[10]^2 = 0.3010 and log[10]^3 = 0.4771.
\n" ); document.write( "Find log[10] ^24
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\n" ); document.write( "I think you mean:
\n" ); document.write( "Solve the problem
\n" ); document.write( "Given \"log%2810%2C2%29+=+0.3010\" and \"log%2810%2C3%29+=+0.4771\"
\n" ); document.write( "Find log(24)
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\n" ); document.write( "1st, base 10 is the default base, called \"common log\", so it's not necessary to specify it.
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\n" ); document.write( "log(2) = 0.3010 and log(3) = 0.4771 is sufficient
\n" ); document.write( "24 = 2*2*2*3
\n" ); document.write( "log(24) = 3*log(2) + log(3)
\n" ); document.write( "log(24) =~ 1.3801
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