document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338751>Question 338751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A container has 6 liters of a 40% alcohol solution in it. How much pure alcohol should be added to raise it to a 60% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242814 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the 100% alcohol required be x liters<BR>\n" );
document.write( "40 % 6 liters<BR>\n" );
document.write( "100% x liters<BR>\n" );
document.write( "60%% (x+6 ) liters<BR>\n" );
document.write( "..<BR>\n" );
document.write( "100x+40*6 = 60*(x+6)<BR>\n" );
document.write( "100x+240=60x+360<BR>\n" );
document.write( "100x-60x=360-240<BR>\n" );
document.write( "40x= 120<BR>\n" );
document.write( "divide by 40<BR>\n" );
document.write( "x= 3 liters<BR>\n" );
document.write( "alcohol required </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );