document.write( "Question 338731: In 1993, the life expectancy of males in a certain country was 69.1 years. In 2000,it was 71.7 years. Let e represent the life expectancy in year t and let t represent the numbers of years since 1993.
\n" ); document.write( "The linear function E(t)that fits the data is
\n" ); document.write( "E(t)=
\n" ); document.write( "Use the function to predict the life expectancy of males in 2005
\n" ); document.write( "E(12)=
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Algebra.Com's Answer #242799 by stanbon(75887)\"\" \"About 
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In 1993, the life expectancy of males in a certain country was 69.1 years.
\n" ); document.write( "(0,69.1)
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\n" ); document.write( "In 2000,it was 71.7 years.
\n" ); document.write( "(7,71.7)
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\n" ); document.write( "slope = (71.7-69.1)/(7-0) = 2.6/7 = 13/35
\n" ); document.write( "intercept = E(0) = 69.1
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\n" ); document.write( "\n" ); document.write( "Let E represent the life expectancy in year t and let t represent the numbers of years since 1993.
\n" ); document.write( "The linear function E(t)that fits the data is
\n" ); document.write( "E(t)= (13/35)t + 69.1
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "Use the function to predict the life expectancy of males in 2005
\n" ); document.write( "E(12)= (13/35)12+69.1
\n" ); document.write( "E(12) = 73.56 years
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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