document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38834>Question 38834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much water must be added to 12 grams of 90% iodine solution to produce a 25% iodine solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24274 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE ORIGINAL SOLUTION CONTAINED 10% WATER TO WHICH X GRAMS OF 100% WATER IS ADDED TO OBTAIN A MIX OR 75% WATER THUS<BR>\n" );
document.write( "12*.1+X=.75(12+X) OR 1.2+X=9+.75X OR .25X=7.8 OR X=7.8/.25 OR X=31.2 GRAMS OF WATER MUST BE ADDED TO GET A SOLUTION OF 75% WATER & 25% IODINE. \r<BR>\n" );
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document.write( "PROOF 12*.1+31.2=.75(12+31.2) OR 1.2+31.2=.75(43.2) OR 32.4=32.4 </SPAN>\n" );
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