document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338649>Question 338649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 25% salt and another solution that is 10% salt. How many liters of each should the chemist use to make 120 liters of a solution that is 15% salt? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242718 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this one.<BR>\n" );
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document.write( "What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 mL of a 40% solution?<BR>\n" );
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document.write( "s = 75% acid volume<BR>\n" );
document.write( "t = 25% acid volume<BR>\n" );
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document.write( "s + t = 500<BR>\n" );
document.write( "0.75s + 0.25t = 0.4*500 = 200 --> x4<BR>\n" );
document.write( "3s + t = 800<BR>\n" );
document.write( "1s + t = 500<BR>\n" );
document.write( "-------------- Subtract<BR>\n" );
document.write( "2s = 300<BR>\n" );
document.write( "s = 150 ml of 75%<BR>\n" );
document.write( "t = 350 ml of 25%<BR>\n" );
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