document.write( "Question 338606: A train leaves the station at 12:00 travling 90 mph and travels 450 miles to its destination. Another train leaves at 12:15 traveling 100 mph from the 1st train's destination. What time will they possibly pass each other? \n" ); document.write( "
Algebra.Com's Answer #242713 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A train leaves the station at 12:00 travling 90 mph and travels 450 miles to its destination. Another train leaves at 12:15 traveling 100 mph from the 1st train's destination. What time will they possibly pass each other? \n" ); document.write( "------------------------------ \n" ); document.write( "1st train DATA: \n" ); document.write( "rate = 90 mph ; distance = x miles ; time = x/90 hrs. \n" ); document.write( "---------------------- \n" ); document.write( "2nd train DATA: \n" ); document.write( "rate = 100 mph ; distance = 450-x miles ; time = (450-x)/100 hrs \n" ); document.write( "-------------------------- \n" ); document.write( "Equation: \n" ); document.write( "1st train time - 2nd train time = 1/4 hr. \n" ); document.write( "------ \n" ); document.write( "x/90 - (450-x)/100 = 1/4 \n" ); document.write( "------ \n" ); document.write( "Multiply thru by 900 to get: \n" ); document.write( "10x - 9(450-x) = 225 \n" ); document.write( "10x - 9*450 + 9x = 225 \n" ); document.write( "19x = 19*225 \n" ); document.write( "x = 225 miles (1st train distance) \n" ); document.write( "1st train time = 225/90 = 2.5 hrs \n" ); document.write( "---- \n" ); document.write( "Clock time when they pass one-another: 2:30 PM \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |