document.write( "Question 338458: Suppose that an object is projected in such a way that its height above the ground in feet after t seconds is given by s(t) = -16t2 +48t + 46. Find the maximum height of the object.
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Algebra.Com's Answer #242667 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Convert to vertex form,
\n" ); document.write( " $\"s%28t%29+=+-16t%5E2+%2B48t+%2B+46\"$
\n" ); document.write( " $\"s%28t%29=-16%28t%5E2-3t%29%2B46\"$
\n" ); document.write( " $\"s%28t%29=-16%28t%5E2-3t%2B9%2F4%29%2B46%2B16%289%2F4%29\"$
\n" ); document.write( " $\"s%28t%29=-16%28t-3%2F2%29%5E2%2B46%2B36\"$
\n" ); document.write( " $\"s%28t%29=-16%28t-3%2F2%29%5E2%2B82\"$
\n" ); document.write( "The max height occurs at the vertex, (3/2,82).
\n" ); document.write( " $\"smax=82\"$ ft.\r
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