document.write( "Question 338565: Please help me solve this equation:-10h>75 \n" ); document.write( "
Algebra.Com's Answer #242657 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"-10h%3E75\"\r
\n" ); document.write( "\n" ); document.write( "There are two approaches\r
\n" ); document.write( "\n" ); document.write( "Approach 1 (the usual one):\r
\n" ); document.write( "\n" ); document.write( "\"-10h%3E75\"\r
\n" ); document.write( "\n" ); document.write( "Use the principle that when both sides of an inequality
\n" ); document.write( "are multiplied or dividied by a negative number the
\n" ); document.write( "inequality sign is reversed, and divide both sides by
\n" ); document.write( "\"-10\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-10h%29%2F%28-10%29%3C75%2F%28-10%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h%3C-15%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Approach 2: without using that principle:\r
\n" ); document.write( "\n" ); document.write( "Add +10h to both sides\r
\n" ); document.write( "\n" ); document.write( "\"-10h%2B10h%3E75%2B10h\"\r
\n" ); document.write( "\n" ); document.write( "\"0%3E75%2B10h\"\r
\n" ); document.write( "\n" ); document.write( "Add -75 to both sides:\r
\n" ); document.write( "\n" ); document.write( "\"-75%3E10h\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by the positive number 10\r
\n" ); document.write( "\n" ); document.write( "\"-75%2F10%3E10h%2F10\"\r
\n" ); document.write( "\n" ); document.write( "\"-15%2F2%3Eh\"\r
\n" ); document.write( "\n" ); document.write( "Both answers are equivalent.\r
\n" ); document.write( "\n" ); document.write( "Edwin\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );