document.write( "Question 338462: the perimeter of a rectangle is 70 inches, and the length is 13 less than twice the width. write a system of 2 equation and solve to find the dimension. \n" ); document.write( "
Algebra.Com's Answer #242639 by unlockmath(1688) You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's have x be one side (length) and y (width) be the other so now we can write 2 equations as: \n" ); document.write( "2x+2y=70 \n" ); document.write( "x=2y-13 \n" ); document.write( "Are you with me? \n" ); document.write( "Now with the second equation subtract 2y from both sides to get: \n" ); document.write( "x-2y=-13 \n" ); document.write( "Now add this to the first to get: \n" ); document.write( "3x=57 \n" ); document.write( "Divide by 3 to get: \n" ); document.write( "x=19 \n" ); document.write( "Plug 19 into the second equation and we get: \n" ); document.write( "y=16 \n" ); document.write( "So now we know the width is 16 inches and the length is 19 inches. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |