document.write( "Question 338462: the perimeter of a rectangle is 70 inches, and the length is 13 less than twice the width. write a system of 2 equation and solve to find the dimension. \n" ); document.write( "
Algebra.Com's Answer #242639 by unlockmath(1688)\"\" \"About 
You can put this solution on YOUR website!
Hello,
\n" ); document.write( "Let's have x be one side (length) and y (width) be the other so now we can write 2 equations as:
\n" ); document.write( "2x+2y=70
\n" ); document.write( "x=2y-13
\n" ); document.write( "Are you with me?
\n" ); document.write( "Now with the second equation subtract 2y from both sides to get:
\n" ); document.write( "x-2y=-13
\n" ); document.write( "Now add this to the first to get:
\n" ); document.write( "3x=57
\n" ); document.write( "Divide by 3 to get:
\n" ); document.write( "x=19
\n" ); document.write( "Plug 19 into the second equation and we get:
\n" ); document.write( "y=16
\n" ); document.write( "So now we know the width is 16 inches and the length is 19 inches.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
\n" ); document.write( "
\n" );