document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338469>Question 338469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 26 meters. Express the A (x) of the rectangle in terms of the length x of one of its sides.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242628 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, perimeter can be found as P = 2L + 2W.\r<BR>\n" );
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document.write( "If the length is x, and the perimeter is 26, we have\r<BR>\n" );
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document.write( "26 = 2x + 2W\r<BR>\n" );
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document.write( "Now solve for W...\r<BR>\n" );
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document.write( "2W = 26 - 2x<BR>\n" );
document.write( "W = 13 - x\r<BR>\n" );
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document.write( "Area is found by length times width...so\r<BR>\n" );
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document.write( "A(x) = LW = x(13-x) </SPAN>\n" );
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