document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338490>Question 338490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave a crossroads at the same time. One heads north at 50km/h and the other heads east at 70km/h. How far apart art the cars after 0.5h? After 2h? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242617 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you make yourself a diagram, you'll notice that the distances represented by the car's travels are the sides of a right triangle...their distance at any time can be found using the Pythagorean Theorem.\r<BR>\n" );
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document.write( "Now remember, rate times time equals ditance...\r<BR>\n" );
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document.write( "After .5 hours, the north side is 25 km, and the east side is 35 km.\r<BR>\n" );
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document.write( "Now apply a^2 + b^2 = c^2 and find c.<BR>\n" );
document.write( "We get c^2 = 25^ + 35^2 = 625 + 1225 = 1850<BR>\n" );
document.write( "c = sqrt(1850) = about 43 km\r<BR>\n" );
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document.write( "Now repeat the procedure for two hours travel...see if you get c = 172 km... </SPAN>\n" );
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