document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338460>Question 338460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two runners start running laps at the same time, from the same starting position. george runs a lap in 50 seconds, sue runs a lap in 30 seconds. when will the runners next be side by side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242597 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s=speed, t=time, d=distance<BR>\n" );
document.write( "st=d<BR>\n" );
document.write( "sue's speed = 1/30 lap/sec, george's=1/50<BR>\n" );
document.write( "the distance is in laps<BR>\n" );
document.write( "time is in secs.<BR>\n" );
document.write( "t=d/s The time of both of them will be equal when george is lapped.<BR>\n" );
document.write( "Let x=number of laps.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(x+1)/(1/30)=x/(1/50)<BR>\n" );
document.write( "(x+1)/50=x/30<BR>\n" );
document.write( "3(x+1)=5x<BR>\n" );
document.write( "3x+3=5x<BR>\n" );
document.write( "2x=3<BR>\n" );
document.write( "x=3/2 laps<BR>\n" );
document.write( "50 * 3/2 = 75 sec. Next time they will be side by side.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );