document.write( "Question 338424: Find two consecutive integers such that 1/3 the smaller plus twice the larger equals 7 more than the sum of the two numbers. \n" ); document.write( "
Algebra.Com's Answer #242582 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let the numbers be x and x+1. \n" ); document.write( "x/3 + 2(x+1)=x+x+1+7 \n" ); document.write( "x/3 + 2x+2=2x+8 \n" ); document.write( "x/3=6 \n" ); document.write( "x=18 \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |