document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338188>Question 338188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the diameter of circle A is twice as large as the diameter of circle B, what is the ratio of the area of the larger circle to the area of the smaller circle?\r<BR>\n" );
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document.write( "(a) 8: 1 (b) 6:1 (c) 4: 1 (d) 2: 1 (e) 3: 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242411 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242411\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the diameter of circle A is twice as large as the diameter of circle B, what is the ratio of the area of the larger circle to the area of the smaller circle? <BR>\n" );
document.write( "(a) 8: 1 (b) 6:1 (c) 4: 1 (d) 2: 1 (e) 3: 2\r<BR>\n" );
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document.write( "area = pi * r^2, r = radius = diameter/2, d = diameter<BR>\n" );
document.write( "area = pi * (d/2)^2 = pi * (d^2)/4   (d/2 * d/2 = (d^2)/4)<BR>\n" );
document.write( "circle B --> pi * (d^2)/4<BR>\n" );
document.write( "circle A (twice as large) --> pi * (2d * 2d)/4 --> pi * (4d^2)/4 --> pi * d^2<BR>\n" );
document.write( "ratio circle A area to circle B area --> (d^2)/((d^2)/4)\r<BR>\n" );
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document.write( "d^2 * 4/(d^2) = 4\r<BR>\n" );
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document.write( "ratio is 4 to 1, so answer is (c) 4:1<BR>\n" );
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