document.write( "Question 338166: I need to find the steps to from
\n" ); document.write( "(7√(2*2*3))/6 to 7/3 √3
\n" ); document.write( "I have been working on it for two days now. I just don't get it.
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Algebra.Com's Answer #242408 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
I need to find the steps to from
\n" ); document.write( "(7√(2*2*3))/6 to 7/3 √3
\n" ); document.write( "I have been working on it for two days now. I just don't get it.\r
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\n" ); document.write( "\n" ); document.write( "let's see if I can figure it out
\n" ); document.write( "sqrt = square root = √\r
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\n" ); document.write( "\n" ); document.write( "(7 * sqrt(2 * 2 * 3))/6 to 7/3 * sqrt(3)
\n" ); document.write( "(if I mistyped or misinterpreted, I apologize)\r
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\n" ); document.write( "\n" ); document.write( "numerator:
\n" ); document.write( "7 * sqrt(12) = 7 * sqrt(4 * 3) = 7 * sqrt(2 * 2 * 3) (factoring)
\n" ); document.write( "7 * sqrt(12) = 7 * 2 * sqrt(3)
\n" ); document.write( "(there were two 2's inside the square root, sqrt(4) = 2)\r
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\n" ); document.write( "\n" ); document.write( "denominator:
\n" ); document.write( "6 = 2 * 3\r
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\n" ); document.write( "\n" ); document.write( "the 2's in the numerator and denominator cancel out\r
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\n" ); document.write( "\n" ); document.write( "left with:
\n" ); document.write( "7/3 * sqrt(3)
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