document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338141>Question 338141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one solution is 20% acid and another is 12%. How many cubic centimeters of each solution should be mixed to obtain 100 cubic centimeters of a solution that is 15% acid. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242391 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .20x+.12(100-x)=.15*100<BR>\n" );
document.write( ".20x+12-.12x=15<BR>\n" );
document.write( ".08x=15-12<BR>\n" );
document.write( ".08x=3<BR>\n" );
document.write( "x=3/.08<BR>\n" );
document.write( "x=37.5 cm^3 of 20% solution is used.<BR>\n" );
document.write( "100-37.5=62.5 cm^3 of 12% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".20*37.5+.12*62.5=.15*100<BR>\n" );
document.write( "7.5+7.5=15<BR>\n" );
document.write( "15=15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );