document.write( "Question 338048: the width of a rectangle is 3feet less than the length. the perimeter is 62feet. find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #242361 by benazir.sj@gmail.com(109) You can put this solution on YOUR website! let the length of the rectangle =x\r \n" ); document.write( "\n" ); document.write( "width =x-3 \n" ); document.write( "given , \n" ); document.write( "perimeter =62ft \n" ); document.write( "2(l+w) =62ft \n" ); document.write( "2(x+x-3) =62ft \n" ); document.write( "2(2x-3)=62ft \n" ); document.write( "4x-6 =62ft \n" ); document.write( "4x=62+6 =68ft \n" ); document.write( "x=68/4 \n" ); document.write( "x=17ft \n" ); document.write( "therefore \n" ); document.write( "length =17 ft \n" ); document.write( "and \n" ); document.write( "width =17-3 \n" ); document.write( " =14ft \n" ); document.write( " |