document.write( "Question 338048: the width of a rectangle is 3feet less than the length. the perimeter is 62feet. find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #242361 by benazir.sj@gmail.com(109)\"\" \"About 
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let the length of the rectangle =x\r
\n" ); document.write( "\n" ); document.write( "width =x-3
\n" ); document.write( "given ,
\n" ); document.write( "perimeter =62ft
\n" ); document.write( "2(l+w) =62ft
\n" ); document.write( "2(x+x-3) =62ft
\n" ); document.write( "2(2x-3)=62ft
\n" ); document.write( "4x-6 =62ft
\n" ); document.write( "4x=62+6 =68ft
\n" ); document.write( "x=68/4
\n" ); document.write( "x=17ft
\n" ); document.write( "therefore
\n" ); document.write( "length =17 ft
\n" ); document.write( "and
\n" ); document.write( "width =17-3
\n" ); document.write( " =14ft
\n" ); document.write( "
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