document.write( "Question 338010: (a) The volume of a cone with a radius r and height h is given by v = 1/3 pr2h. Rearrange this formula to make the subject r.
\n" ); document.write( "(b) The formula S =prvr2+h2 gives the area of the curved surface of the cone. Rearrange this formula to make the subject h.
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Algebra.Com's Answer #242320 by nyc_function(2741)\"\" \"About 
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(a) The volume of a cone with a radius r and height h is given by v = 1/3 pr^2h. Rearrange this formula to make the subject r.\r
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\n" ); document.write( "\n" ); document.write( "v = 1/3 pr^2h\r
\n" ); document.write( "\n" ); document.write( "3v = pr^2h\r
\n" ); document.write( "\n" ); document.write( "3v/ph = r^2\r
\n" ); document.write( "\n" ); document.write( "sqrt[3v/ph] = sqrt[r^2]\r
\n" ); document.write( "\n" ); document.write( "sqrt[3v/ph] = r\r
\n" ); document.write( "\n" ); document.write( "Done!\r
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\n" ); document.write( "\n" ); document.write( "(b) The formula S = prvr^2+h^2 gives the area of the curved surface of the cone. Rearrange this formula to make the subject h.\r
\n" ); document.write( "\n" ); document.write( "S = prvr^2+ h^2\r
\n" ); document.write( "\n" ); document.write( "S - prvr^2 = h^2\r
\n" ); document.write( "\n" ); document.write( "sqrt[S - prvr^2] = sqrt[h^2]\r
\n" ); document.write( "\n" ); document.write( "r(sqrt[S - prv]) = h\r
\n" ); document.write( "\n" ); document.write( "Done!\r
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