document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=338009>Question 338009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12 degrees less than one half the supplement of an angle is the same as the complement. Find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #242317 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=242317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = the angle\r<BR>\n" );
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document.write( "Let (180 - A) = the supplement of the angle\r<BR>\n" );
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document.write( "Let (90 - A) = the complement of the angle\r<BR>\n" );
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document.write( "(1/2)(180 - A) - 12 = (90 - A)\r<BR>\n" );
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document.write( "I'll let you take it from here.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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