document.write( "Question 4895: log (6x + 5) - log 3 = log 2 - log x
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Algebra.Com's Answer #2423 by arunpaul(104)\"\" \"About 
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log (6x + 5) - log 3 = log 2 - log x
\n" ); document.write( "log (6x + 5) +log x = log 2+log 3\r
\n" ); document.write( "\n" ); document.write( "log ((6x + 5)*x)= log (2*3)
\n" ); document.write( "taking the anti log we have\r
\n" ); document.write( "\n" ); document.write( "(6x+5)*x = 2*3
\n" ); document.write( "6x^2+5x-6 =0
\n" ); document.write( "putting it in solution of quadratic equation the solution = .667 and -1.5
\n" ); document.write( "since log( -1.5 ) is undefined, only 0.667 is the solution.\r
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