document.write( "Question 337942: 1) \"+x%5E2%2B2x%2Bx%5E2-4=36+\"
\n" ); document.write( "i get confused on how to eliminate exponets. I'm solving for x.\r
\n" ); document.write( "\n" ); document.write( "2)\"+%28x%2B16%29%2F5+\"
\n" ); document.write( "I don't know how to solve this at all. Please explain step by step!
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Algebra.Com's Answer #242275 by katealdridge(100)\"\" \"About 
You can put this solution on YOUR website!
#1
\n" ); document.write( "First, simplify the equation by combining like terms.
\n" ); document.write( "\"2x%5E2%2B2x-4=36\"
\n" ); document.write( "This is a quadratic equation (the x is squared) so you have to set the equation equal to zero by subtracting 36 from both sides.
\n" ); document.write( "\"2x%5E2%2B2x-40=0\" Everything here can be divided by 2 to make the problem simpler. You can do this in a equation as long as you do it to both sides.
\n" ); document.write( "\"x%5E2%2Bx-20=0\" Now you can factor this quadratic to find the answer most easily.
\n" ); document.write( "\"%28x%2B5%29%28x-4%29=0\" This is the equation factored. You need to look for two numbers that multiply to 20 and add or subtract to 1 (the middle number). These numbers are 4 and 5.
\n" ); document.write( "Then set each equation equal to 0.
\n" ); document.write( "\"x%2B5=0\"\"x-4=0\" Solve each for x.
\n" ); document.write( "x=-5, x=4. These are your answers. Most quadratics have two answers.
\n" ); document.write( "#2 isn't an equation, so you can't solve it. I would assume there is some info missing. If you need more help on factoring, please ask.
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