document.write( "Question 4561: Please help! I can not figure out two problems. I am to determine whether the following system is consistent, inconsistent, or dependent. If the system is consistent, find the solution of the system.
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document.write( "The first problem is :\r
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document.write( " 6x + 4y =8
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document.write( " 9x + 6y =12\r
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document.write( "and the second problem is:\r
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document.write( " 2/3x + 3/4y =4
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document.write( " 5/6x - 3/8y = -11/2\r
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Algebra.Com's Answer #2422 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! 6x + 4y =8 \n" ); document.write( "9x + 6y =12\r \n" ); document.write( "\n" ); document.write( "Multiply the second equation by 2/3: \n" ); document.write( "6x + 4y = 8 \n" ); document.write( "6x + 4y = 8\r \n" ); document.write( "\n" ); document.write( "These are identical so they are the same line!\r \n" ); document.write( "\n" ); document.write( "Second problem:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since I don't want to work with fractions, I will: \n" ); document.write( "Multiply the first equation by 12 to clear the denominators \n" ); document.write( "Multiply the second equation by 24 to clear the denominators\r \n" ); document.write( "\n" ); document.write( "8x + 9Y = 48 \n" ); document.write( "20x- 9y = -132\r \n" ); document.write( "\n" ); document.write( "Add them together: \n" ); document.write( "28x = -84 \n" ); document.write( "Divide both sides by 28: \n" ); document.write( "x=3\r \n" ); document.write( "\n" ); document.write( "substitute back into either equation: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Clear parentheses: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 2 from each side: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides by 4/3: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "check by putting x and y back into the second equation to validate:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "this is not a true statement, so this problem has no solution. \n" ); document.write( " \n" ); document.write( " |